OB = 1
OA = L
BA = X
AB is perpendicular to OB
OBC and AOB are similiar triangles
angle OBC and AOB are equal
y-length of AB relative to O:
y-length = ln(L + X)
h-length of AB relative to O:
h-length = ln(L)
If h-length is subtracted from y-length, and the difference is used
as an exponent to the base e, that amount equals 1 + OC.
eylength - hlength = 1 + OC
in the diagram:
AB = .57735
OA = 1.1547
OC = .5
e.549306 - .143841
= e.405464
= 1.5
= 1 + .5