e raised to the power of h-length multiplied by 2

OB = 1
OA = L
BA = X
AB is perpendicular to OB
ABC and AOB are similiar triangles
angle CAB and AOB are equal

h-length of BA, relative to O:
h-length = ln(L)

e^2hlength = 1 + CB

in the diagram:
AB = .7
OB = 1
OA = 1.22065
CB = .49

h-length of BA, relative to O, is .199388

e^2(.199388) = 1.49
= 1 + .49
= 1 + CB