OB = 1
L2 = 2, L3 = 3, etc.
If OB and the diagonals L2, L3, L4.... Ln form
the arithmetic progression 1, 2, 3, 4, .... n, the corresponding h-length segments represent
the harmonic series 1, 1/L2, 1/L3 ..... 1/Ln. As n approaches
infinitely large, the sum of these vertical segments represent the sum of the harmonic
series.
An approximation of each term can be made by taking the h-length between corresponding
diagonals along the line BA, relative to O. e.g. The vertical segment 1/2, being the
reciprocal of L2, can be approximated by taking the h-length of the segment
B3B2, relative to O.
ln 3 - ln 2 = ln 3/2 = .405465
The approximation of any vertical segment which is a term in the harmonic series,
can be expressed as
ln (Ln + 1) / Ln = approx. of the harmonic term
As n becomes larger the approximation becomes more exact.
As n becomes infinitely large, the difference between the h-length of the line up
to Bn and the sum of the harmonic series up to that same point, approaches
the value of Euler's constant (.577218). This constant could be thought of as the
difference between the h-length of BA, as Ln approaches infinitely large,
and the sum of those segments of h-length represented when the diagonals are
increasing by an arithmetic progression of one. (i.e. the harmonic series)